Section 2.1: Frequency Distributions & Their Graphs
1. Calculating Class Width & Limits:
A data set has a minimum value of 45 and a maximum of 132. Construct a frequency distribution with 6 classes. Find the Class Width and the Lower/Upper limits for the first two classes.
Step 1 (Range): Range = Max - Min = 132 - 45 = 87[cite: 43, 762].Step 2 (Width): Width = Range / #Classes = 87 / 6 = 14.5. Round up to 15[cite: 44, 45, 74].Step 3 (Limits): Class 1 Lower Limit = 45 (min)[cite: 50, 78].Class 2 Lower Limit = 45 + 15 = 60[cite: 51, 81].Class 1 Upper Limit = 60 - 1 = 59[cite: 52, 99].Results: Class 1: (45-59), Class 2: (60-74).
2. Complete Frequency Distribution Table:
Complete the table for 40 data entries (n=40, width=10). Calculate Midpoint (x), Relative Frequency, and Cumulative Frequency.
For the class (70 - 79), calculate the Lower and Upper Class Boundaries.
Rule: Subtract 0.5 from Lower Limit and add 0.5 to Upper Limit[cite: 158, 159].Lower Boundary: 70 - 0.5 = 69.5.Upper Boundary: 79 + 0.5 = 79.5.
Section 2.2: More Graphs & Displays
4. Ordered Stem-and-Leaf Plot:
Construct an ordered stem-and-leaf plot for the following data: 21, 25, 30, 25, 36, 45, 27.
Step 1 (Stems): Use the tens place: 2, 3, 4[cite: 296].Step 2 (Leaves): List the ones place for each stem and order them[cite: 336].2 | 1 5 5 73 | 0 64 | 5Key: 2 | 1 = 21[cite: 311].
5. Pie Chart (Central Angle):
If a category has a relative frequency of 0.35, find the central angle for the pie chart.
Calculate the Mean and Median. Explain why the Median is a better "typical" measure here.
Mean (x̄): Σx / n = (10+12+12+14+15+95) / 6 = 158 / 6 ≈ 26.3[cite: 482, 603].Median: Average of the two middle values (12 and 14) = (12+14)/2 = 13[cite: 509, 604].Explanation: 95 is an outlier[cite: 589]. The Mean is heavily pulled toward the outlier, while the Median is resistant and reflects the center better[cite: 612, 614].
7. Mean of Grouped Data (Table):
Calculate the estimated sample mean from the following frequency distribution.
A bell-shaped distribution has x̄ = 100 and s = 15. What percentage of data falls between 70 and 130?
Step 1: Distance from mean = (130 - 100) / 15 = 2 standard deviations[cite: 1025].Rule: Approximately 95% of data falls within 2 standard deviations[cite: 1025, 1028].
Section 2.5: Measures of Position
11. Five-Number Summary:
Data Set: 5, 7, 12, 15, 18, 22, 30
Find the Five-Number Summary and IQR.
1. Minimum: 5[cite: 1057, 1064].2. Q1 (Median of lower half): Median of {5, 7, 12} = 7[cite: 1048, 1049].3. Median (Q2): Middle value = 15[cite: 1041, 1047].4. Q3 (Median of upper half): Median of {18, 22, 30} = 22[cite: 1042, 1049].5. Maximum: 30[cite: 1057, 1064].IQR: Q3 - Q1 = 22 - 7 = 15[cite: 1053, 1055].
12. Z-Score Calculation:
Value (x) = 85, Mean (μ) = 70, Std Dev (σ) = 5. Calculate and interpret the z-score.
Formula: z = (x - μ) / σ[cite: 1067].Calculation: (85 - 70) / 5 = 15 / 5 = 3.0[cite: 1067].Interpretation: The value 85 is 3.0 standard deviations above the mean.